C^2+6+c^2+2=2(4c)

Solution for C^2+6+c^2+2=2(4c) equation:

^2+6+C^2+2=2(4C)

We move all terms to the left:

^2+6+C^2+2-(2(4C))=0

determiningTheFunctionDomain
C^2-24C+6+2+^2=0

We add all the numbers together, and all the variables

C^2-24C=0

a = 1; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·1·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*1}=\frac{0}{2}
=0
$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*1}=\frac{48}{2}
=24
$